Construct isosceles trapezium ABCD with the following measurements and find its area.

is parallel to AB = 10 cm, DC = 6 cm and AD = BC = 7 cm.

Given. ABCD is a isosceles trapezium.

AB = 10 cm, DC = 6 cm and AD = BC = 7 cm

Formula used. Area of trapezium = × height × sum of parallel sides

Area of trapezium = × height × (PQ + SR)

Steps of Construction

Step 1 : Draw a line AB of 10cm

Step 2 : Mark a point E on AB such that AE = 6cm and EB = 4cm

Step 3 : Make arc of 7cm from both point E and B

Step 4 : Mark the intersecting point of both arcs to be C and join EC and EB

Step 5 : Draw arcs of 6cm and 7cm from point C and A respectively

Step 6 : Mark the intersection point of both arcs as D

Step 7 : Join AD and CD to form trapezium ABCD

Step 8 : Draw a perpendicular on AB from point C and name the intersection point as F

Area of trapezium = × height × (AB + CD)

= × RF × (AB + CD)

= = × 6.7cm × (10cm + 6cm)

= 53.6cm²

Conclusion. Hence; Trapezium ABCD is constructed and its area is

53.6cm²