Draw parallelogram ABCD with the following measurements and calculate its area.

AB = 5.5 cm, ∠DAB = 50° and BD = 7 cm.

Given. ABCD is a parallelogram.

AB = CD ; BC = AD , AB = 5.5 cm, BD = 7 cm

∠DAB = 50°

Formula used. Area of parallelogram = base × height

Steps of Construction

Step 1 : Draw AB of length 5.5cm

Step 2 : Make an angle of 50° on point A and extend the ray AD’

Step 3 : Make an arc of 7cm from point B on ray AD’ and also note Down the length of AD

Step 4 : Make an arc of 5.5cm from point D and another arc of same length of AD from point B

Step 5 : Mark the intersection point as C and join AC and CD

Step 6 : Draw a perpendicular on AB from point C and name the

intersection point as E

Area of parallelogram = base × height

= AB × CE

= 5.5cm × 7cm

= 38.5cm²

Conclusion. Hence; parallelogram ABCD is constructed and its area is 38.5cm²