Q2 of 8 Page 54

Four times a number and three times a number added together make 43. Two times the second number, subtracted from three times the first give 11. What are the numbers?

Let the first number be ‘x’ and second number be ‘y’.


According to the question,


Four times a number and three times a number added together make 43


⇒ 4x + 3y = 43 … (1)


Two times the second number, subtracted from three times the first give 11


⇒ 3x – 2y = 11 … (2)


Equating equation (1) and (2)


4x + 3y = 43 … (1)


3x – 2y = 11 … (2)


Multiply equation (1) by 2 and (2) by 3




x = 7


Put x = 7 in equation (4)


9 × 7 – 6y = 33


⇒ 63 – 6y = 33


⇒ 63 = 33 + 6y


⇒ 6y = 63 – 33


⇒ 6y = 30


⇒


⇒ y = 5


Hence the two numbers are 7 and 5.


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