The hypotenuse of a right triangle is
centimetres and its area are
square centimetres. Calculate the lengths of its perpendicular sides.
Let the base be ‘x’ and perpendicular be ‘y’.
Area of triangle ![]()
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⇒ 15 = xy … (1)
By Pythagoras Theorem,
(Base)2 + (Height)2 = (hypotenuse)2
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… (2)
From equation (1),
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⇒ 2(x2 + 15) = 17 × x
⇒ 2x2 + 30 = 17x
⇒ 2x2 – 17x + 30 = 0
⇒ 2x2 – 12x - 5x + 30 = 0
⇒ 2x (x – 6) – 5(x – 6) = 0
⇒ (2x – 5) (x – 6) = 0
2x – 5 = 0 or x – 6 = 0
2x = 5 or x = 6
or x = 6
Put
in equation (2)
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Put x = 6 in equation 2
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∴ Base of triangle can be
or 6
Perpendicular of triangle can be
or 6.
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