A wire was bent into a circle of diameter 4 centimetres. What would be the diameter of a circle made by bending a wire of half the length?
Diameter of circle = 4 cm
Length of wire = Circumference of circle
If r = radius of circle
Circumference of circle = 2 × π × r=2 × π × 4
=8 × π
If length of wire is halved,
Circumference is also halved
∴ New Circumference = 1/2 × (8 × π)= 4 × π
Let r’be new radius
∴ 2 × π × r'= New Circumference = 4 × π
∴ r’ = ![]()
Hence, New diameter = 2 × r'= 2 × 2=4 cm
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