Q2 of 18 Page 163

An isosceles triangle with its vertices on a circle is shown in this picture.


What is the perimeter of the circle?

The figure is shown below:



Let OA = radius of circle.


AD = 1 cm


OA = r


OD = 1-r


OA = OB = r


In triangle OBD,


ODB = 90°


AB = AC and AD is perpendicular on BC from point A.


BD = DC =


By pythagoras theorem,


(Hypotenuse)2 = (One side)2 + (Other side)2


(OB)2 = (OD)2 + (BD)2


r2 = (1-r)2 + ()2


r2- (1-r)2 =


(r + {1-r})(r-{1-r}) = {a2-b2 = (a + b) × (a-b)}


1 × (2r-1) =


2r =


r =


If r = radius of circle


Circumference =


Perimeter =


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