Prove that the arithmetic sequence with first term 1/3 and common difference 2/3 contains all odd numbers, but no even number.
For the sequence,
a = ![]()
d = ![]()
an = a + (n-1) × d
=
+ (n-1) × ![]()
= ![]()
= k(2n-1) (where k = constant)
As an is a multiple of (2n-1) and not (2n) it contains all odd numbers but no even number..
Couldn't generate an explanation.
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