(i) Here, we will use formula in which we can calculate sum of AP by first term(a) and last term(an) i.e.
![]()
Where n is no of terms
Clearly first term, a = 51
Last term, an = 70
And no of terms, n = 70 - 51 + 1 = 20
Hence, sum is ![]()
= 10(121)
= 1210
(ii)
Here, we will use formula in which we can calculate sum of AP by first term(a) and last term(an) i.e.
![]()
Where n is no of terms
Clearly first term, ![]()
Last term, ![]()
Common difference, ![]()
Therefore, we can calculate no of terms usinh,
![]()
![]()
⇒ 11 = n - 1
⇒ n = 12
Hence, we have sum as
![]()
⇒ Sn = 6(14) = 84
(iii)
Here, we will use formula in which we can calculate sum of AP by first term(a) and last term(an) i.e.
![]()
Where n is no of terms
Clearly first term, ![]()
Last term, ![]()
Common difference, ![]()
Therefore, we can calculate no of terms usinh,
![]()
![]()
![]()
⇒ n = 25
Hence, we have sum as
![]()
![]()
![]()
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