Q6 of 46 Page 249

A bomb of mass 3 kg, initially at rest, explodes into two parts of 2 kg and 1 kg. The 2 kg mass travels with a velocity of 3 m/s. At what velocity will the 1 kg mass travel?

Let M = 3 kg(the mass of the bomb)

m1 = 2 kg(mass of one of the pieces)


m2 = 1 kg(mass of the other piece)


v1 = 3 m/s


v2 = ?


Initial momentum = 0(because the bomb was at rest)


According to the law of conservation of momentum,


Initial momentum = final momentum


0 = m1v1 + m2v2



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