A bomb of mass 3 kg, initially at rest, explodes into two parts of 2 kg and 1 kg. The 2 kg mass travels with a velocity of 3 m/s. At what velocity will the 1 kg mass travel?
Let M = 3 kg(the mass of the bomb)
m1 = 2 kg(mass of one of the pieces)
m2 = 1 kg(mass of the other piece)
v1 = 3 m/s
v2 = ?
Initial momentum = 0(because the bomb was at rest)
According to the law of conservation of momentum,
Initial momentum = final momentum
0 = m1v1 + m2v2
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.