Q7 of 46 Page 249

Two ice skaters of weight 60 kg and 50 kg are holding the two ends of a rope. The rope is taut. The 60 kg man pulls the rope with 20 N force. What will be the force exerted by the rope on the other person? What will be their respective acceleration?

The figure of the question is given below:



It is given in the question that the rope is taut, it means the rope is very tight.


Hence, the force exerted will be the same when on both the sides of the rope. i.e. The force exerted by the rope on the other person will also be 20 N, according to Newton’s 3rd law of motion.


Now, the acceleration of the 60 kg man




= 0.33 ms-2


The acceleration of the 50 kg man




= 0.4 ms-2


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