Q4 of 40 Page 128

The number of protons, neutrons and electrons present respectively in 8035Br

Atomic number = Total no. of electrons = 35

Now, No. of electrons = No. of Protons = 35


And, Mass Number = Protons + Neutrons = 80


No. of neutrons = Mass no. – Protons


= 80 – 35 = 45

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