A metal combines with oxygen to form two oxides having the following composition

i) 0.398 gram of metal oxide I contains 0.318 gram of metal

ii) 0.716 gram of metal oxide II contains 0.636 gram of metal. So that the above data agrees with the law of multiple proportions.

i) 0.398g metal oxide contains 0.318g of metal.

Therefore, amount of oxygen combining with

0.318g metal oxide I = 0.398-0.318 = 0.080g

ii) 0.716g metal oxide contains 0.636g of metal.

Therefore, amount of oxygen combining with

0.318g metal oxide I = 0.716-0.636 = 0.080g

Thus, for fixed mass of oxygen (0.080g), the metal forma oxides in the ratio = 0.318:0.636 = 1:2

Since, it is a simple ratio therefore the above data agrees with the law of multiple proportion.