In the figure below, M is the midpoint of the line AB. Compute the other two angles of ∆ABC.

Given, M is the midpoint of the line AB and ∠m = 90⁰.
∠a = 50
We know sum of all interior angles of a triangle is 180⁰.
In ∆AMC,
∠a + ∠b + ∠c = 180⁰
50⁰ + 90 + ∠c = 180⁰
140⁰ + ∠c = 180⁰
∠c = 180⁰-140⁰
∠c = 40⁰
In ∆MBC,
∠c = 40⁰
∠m = 90⁰
∠b = ?
∠m + ∠b + ∠c = 180⁰
90⁰ + ∠b + 40⁰ = 180⁰
130⁰ + ∠b = 180⁰
∠b = 180⁰-130⁰
∠b = 50⁰

∠a = 50⁰, ∠b = 50⁰, ∠c = 80⁰
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