Are the two diagonals of a rectangle equal? Why?

A rectangle is a parallelogram where each angle is a right angle.
Here, AD = BC …(eq)1
And AB = CD
According to Pythagoras theorem,
(Hypotenuse)2 = (one side)2 + (other side)2
In Δ ABD,
Hypotenuse = BD
One side = AB
And other side = AD
∴ (BD)2 = (AB)2 + (AD)2 …(eq)2
In Δ ABC,
Hypotenuse = AC
One side = AB
And other side = BC
∴ (AC)2 = (AB)2 + (BC)2
= (AB)2 + (AD)2 …(eq)3 …(from eq1)
As is clear from (eq)2 and (eq)3
BD2 = AC2
Taking square root on both sides,
BD = AC
∴ Diagonals of a rectangle are equal.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.


