Acid and water are mixed in the ratio 4 : 3 to make a liquid. On adding 10 more litres of Acid, the ratio changed to 3 : 1. How many litres of acid and water does the liquid contain now?
Let us assume the actual quantity of acid as 4x and water as 3x.
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Now,
On adding 10 more litres of Acid, ratio becomes 3: 1
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⇒ ![]()
⇒ 1 × (4x + 10) = 3 × 3x
⇒ 4x + 10 = 9x
⇒ 9x – 4x = 10
⇒ 5x = 10
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New quantity of Acid = 4x + 10
= 4×2 + 10
= 8 + 10 = 18
New Quantity of Water = 3x
= 3×2 = 6
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