The oxidation state of oxygen is -2. Find the oxidation state of the other atoms in the following compounds.
1. H2O 2. H2CO3 3. HNO3 4. H3PO4
Note: the sum of oxidation numbers of all elements in a compound is zero.
Consider x is the oxidation number of atoms whose oxidation number is to be found. Oxidation number of oxygen is -2. Applying the above rule-
1. 2x + (-2) = 0 ; x = 1 ; oxidation number of hydrogen is 1.
2. 2(1) + x + 3(-2) = 0 ; x = 4 ; oxidation number of carbon is 4.
3. 1 + x + 3(-2) = 0 ; x = 5 ; oxidation number of nitrogen is 5.
4. 3(1) + x + 4(-2) = 0 ; x = 5 ; oxidation number of phosphorous is 5.
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