Q5 of 9 Page 137

A potential difference of 6 V is applied across a conductor having 12 Ω resistance. How much current will pass through it?

How many times will the current increase if length of the resistor is halved and potential difference is doubled?

Using V=IR where V is Voltage; I is the current and R is the resistance, the current that will pass is 0.5 Ampere.

Since resistance is directly proportional to length, if the length is halved then resistance will be halved; hence new resistance will be 6Ω.


Now, the potential difference is doubled i.e. 12V; So now the current changes to 2 Ampere.


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