Draw the method of connecting four resistors of 2 Ω each to get
.
No possible Method
Since we have 4 resistors of 2Ω each; so maximum resistance that we can get is 8Ω and minimum is 2Ω. So, our first thought would be that we can solve the above problem.
And we try 1 resistor in series with other 3 in parallel and we don’t get the above-given resistance. On trying other possible combination, we don’t get; hence the above problem is not correct and there is no a possible method.
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