Q6 of 27 Page 46

Given below are a few samples.

a. 400 g of water (H2O)


b. 400 g of carbon (C)


c. 400 g of helium (He)


d. 400 g of hydrogen (H2)


e. 400 g of glucose (C6H12O6)


(i) Find the number of moles in each.


(ii) Arrange the samples in the increasing order of their number of moles.


(Gram molecular masses He = 4 g, C = 12 g, H2 = 2 g, H2O = 18 g, C6H12O6 = 180 g)

One mole: The amount of any substance containing 6.022 × 1023 particles is called one mole.

a. Given: Mass of water = 400g


Gram molecular mass (GMM) of H2O = 18g


Apply the formula:




Number of moles = 22.2


Thus, number of moles of the given sample is 22.2


b. Given: Mass of carbon = 400g


Gram molecular mass (GMM) of carbon = 12g


Apply the formula:




Number of moles = 33.3


Thus, number of moles of the given sample is 33.3


c. Given: Mass of helium = 400g


Gram molecular mass (GMM) of He = 4g


Apply the formula:




Number of moles = 100


Thus, number of moles of the given sample is 100


d. Given: Mass of hydrogen = 400g


Gram molecular mass (GMM) of H2 = 2g


Apply the formula:




Number of moles = 200


Thus, number of moles of the given sample is 200


e. Given: Mass of glucose = 400g


Gram molecular mass (GMM) of C6H12O6 = 180 g


Apply the formula:




Number of moles = 2.22


Thus, number of moles of the given sample is 2.22


ii) Arrangement of the samples in the increasing order of their number of moles is:


Glucose < Water <Carbon < Helium < Hydrogen


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