Examine the samples given:

a. 20 g of He

b. 44.8 L of NH₃ at STP

c. 67.2 L of N₂ at STP

d. 1 mol of H₂SO₄

e. 180 g of water

What will be the masses of samples b, c and d?

Calculation of mass:

For 44.8 L of NH₃ at STP (b)

Number of moles = 2 (calculated in part (i)-b)

Now, we can calculate the mass of NH₃ by applying the formula given:

We can write,

Mass of NH₃ = Number of moles × GMM of NH₃

Mass of NH₃ = 2 × 17g

Mass of NH₃ = 34g

Thus, mass of 44.8L of NH₃ at STP is 34g

For 67.2 L of N₂ at STP (c)

Number of moles = 3 (calculated in part (i)-c)

Now, we can calculate the mass of N₂ by applying the formula given:

We can write,

Mass of N₂ = Number of moles × GMM of N₂

Mass of N₂ = 3 × 28g

Mass of N₂ = 84g

Thus, mass of 67.2 L of N₂ at STP is 84g

1 mol of H₂SO₄

Number of moles = 1

Now, we can calculate the mass of H₂SO₄ by applying the formula given:

We can write,

Mass of H₂SO₄ = Number of moles × GMM of H₂SO₄

Mass of H₂SO₄ = 1 × 98g

Mass of H₂SO₄ = 98g

Thus, mass of 1 mol of H₂SO₄ is 98g