A cylindrical container having diameter 16 cm and height 40 cm is full of ice - cream. The ice - cream is to be filled into cones of height 12 cm and diameter 4 cm, having a hemispherical shape on the top. Find the number of such cones which can be filled with the ice - cream.
Given.
Radius of Hemispherical bowl and cone is
= 2 cm
Cylindrical container of diameter 16 cm and height 40 cm
Formula used/Theory.
Volume of Cylinder = πr2h
Volume of hemisphere =
πr3
Volume of Cone =
πr2h
Volume of ice - cream will be equal to sum of volume of hemisphere bowl and volume of cone
Volume of hemisphere =
πr3
=
× π × (2 cm) 3
=
π cm3
Volume of Cone =
πr2h
=
× π × (2 cm) 2 × 12 cm
16π cm3
Volume of ice - cream = 16π cm3 +
π cm3
=
× 16π cm3
Radius of container =
= 8 cm
Volume of container = πr2h
= π × (8cm) 2 × 40 cm
= 2560π cm3
**Note we will not put value of π as it will be divided in next step
Number of ice - cream will be dividing the total volume of ice - cream in container by volume of ice - cream contained by 1 cone
Number of ice - creams = ![]()
= 120
∴ 120 ice - cream can be filled by the container
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