Q5 of 38 Page 31

If x + z = 2y and b2 = ac, then let us show that ay–z bz–x cx–y = 1.

Given that x + z = 2y and b2 = ac

We can write from x + z = 2y


…eq(1)


Now, b2 = ac





Now, we can write as


and …eq(2)


Now, LHS = ay–z bz–x cx–y






= b0 = 1 = RHS


Therefore, LHS = RHS


Hence, proved .


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