Q7 of 38 Page 31

If and xyz = 1, then let us show that a + b + c = 0.

Given and xyz = 1

Let


Therefore,


…eq(1)



…eq(2)



…eq(3)


Now, xyz = 1



(from eq(1), eq(2)and eq(3))




We know that if base of the exponents are same then the powers are also equal.


Therefore, a + b + c = 0.


Hence the relation is proved.


More from this chapter

All 38 →
5

If x + z = 2y and b2 = ac, then let us show that ay–z bz–x cx–y = 1.

 6

If a = xyp–1, b = xyq–1 and c = xyr–1, then let us show that aq–r br–p cp–q = 1.

 8

If ax = by = cz and abc = 1, then let us show that xy + yz + zx = 0.

 9

Let us solve:

49x = 73