Draw an equilateral triangle with length of side 6.5 cm and let us draw a parallelogram equal in area to that triangle and having an angle 45°.
Steps of Construction:
1. We draw a triangle ABC of given dimensions.

2. We draw a perpendicular bisector of side AB which intersects AB at D.
3. Join C to D.

4. Draw a line parallel to AB through C by completing the parallelogram ACQB.

5. From D, construct ∠GDB=45°.
6. The line cuts parallel line through C at E.

7. From E, cut an arc of length DB on the parallel line.
8. Mark the point as F.
9. Join F to B.
10. DBFE is the required parallelogram.

Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

