Q7 of 7 Page 239

Let us draw an isosceles triangle whose equal sides are of length 8 cm. and angle between them is 30°. Let us draw a rectangle whose area is equal to the above isosceles triangle.

Steps of Construction:


1. We draw a triangle ABC of given dimensions.



2. We draw a perpendicular bisector of side AB which intersects AB at D.


3. Join C to D.



4. Draw a line parallel to AB through C by completing the parallelogram ACQB.



5. As we have to draw a rectangle of same area. We can use the perpendicular bisector drawn through D.


6. The perpendicular bisector cuts parallel line through C at E.


7. From E, cut an arc of length DB on the parallel line.


8. Mark the point as F.


9. Join F to B.


10. DBFE is the required rectangle.



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