I draw a square with side 5 cm. I draw a parallelogram with equal area of square of which one angle is 60°.
A. Draw the given square ABCD.

B. Draw the diagonal DB of square ABCD.
C. Draw a parallel line through point C to diagonal DB of square ABCD which intersects at E produced AB.
D. CE||DB.

Proof:
Since sides of square are equal and parallel, AB||DC and thus, DC||AE.
∴ square ABCD = ∆ABE (on same base DC and between same parallels DC and AE)
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