Q6 of 8 Page 244

I draw a square with side 6 cm. and I draw a triangle with equal area of that square.

A. Draw the given square ABCD.



B. Draw the diagonal DB of square ABCD.


C. Draw a parallel line through point C to diagonal DB of square ABCD which intersects at E produced AB.


D. CE||DB. ΔADE is the required triangle.



Proof:


∆DCB = ∆DBE (on same base DB and between same parallels DB and CE)


∴ ∆DCB = ∆DBE


∆ABD + ∆DCB = ∆DBE + ∆ABD (adding area of ∆ABD on both sides)


∴ square ABCD = ∆ADE


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