Three medians AD, BE and CF of ΔABC intersect each other at the point G. If area of ΔABC is 36 sq. cm, let us calculate.

(i) Area of ΔAGB

(ii) Area of ΔCGE

(iii) Area of quadrilateral BDGF.

Given: area of ABC is 36 sq cm

(i) As we know if three medians AD, BE and CF of a ΔABC intersect one another at the point G (centroid) then,

Area of ΔABC = 3 × Δ AGB

⇒ Area of ΔAGB =

⇒ Area of ΔAGB = 12 sq. cm

(ii) As we know if three medians AD, BE and CF of a ΔABC intersect one another at the point G (centroid) then,

Area of ΔABC = 6 × Δ GEC

⇒ Area of ΔGEC =

⇒ Area of ΔGEC = 6 sq. cm

(ii) As we know if three medians AD, BE and CF of a ΔABC intersect one another at the point G (centroid) then,

Area of ΔABC = 3 × Δ BDGF

⇒ Area of ΔBDGF =

⇒ Area of ΔBDGF = 12 sq. cm