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17. Theorems on concurrence
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Q1 of 24 Page 296

O is the circumcentre of ABC; if ∠BOC = 80° the ∠BAC is

Given:



As we know,


If O is circumcenter of Δ ABC then:


∠BOC = 2 ∠BAC (Application 1)




⇒ ∠BAC = 40°


Option (A) is correct.

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AD, BE and CF are the medians of ΔABC. If AD = BC, then let us prove that the angle between two medians is 90°.

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P and Q are the mid points of sides BC and CD of a parallelogram ABCD respectively; the diagonals AP and AQ cut BD at the points K and L. Let us prove that, BK = KL = LD.

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O is the orthocenter of ABC; if ∠BAC = 40° the ∠BOC is

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Questions · 24
17. Theorems on concurrence
1 2 3 1 2 1 2 3 4 5 6 7 8 9 1 1 1 1 1 11 11 11 11 11
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