The point s A and B lie on 2nd and 4th quadrant respectively and distance of each point from x – axis and y – axis are 8 units and 6 units respectively. Let us write the co – ordinate of mid-point of line segment AB.
The coordinates of point A will be –(– 8, 6), because it lies in 2nd quadrant. And point B will be (8, – 6), because it’s in 4th quadrant.
Let the co-ordinates of mid-point of PR be (x, y).
And, since it is a mid-point –
![]()
![]()
⇒ x = 0 and y = 0
⇒ The mid-point is actually the origin(0, 0).
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.