Q1 of 34 Page 342

Let us evaluate:

(i)


(ii) log0.01 0.000001


(iii)


(iv)

(i)



As, logaMc = c logaM



(ii)



As, logaMc = c logaM



[As, logaa = 1]


(iii)



As, logaMc = c logaM



[As, logaa = 1]


(iv)



= log√3(√3)6


= 6(log√3√3) [As, logaMc = c logaM]


= 6(1) [As, logaa = 1]


= 6


More from this chapter

All 34 →
2

Let us write by calculating, find its base if logarithm of 625 is 4

 2

Let us write by calculating, find its base if logarithm 5832 is 6

 3

If 1 + log10a = 2log10b, then express a by b

 3

If 3 + log10x = 2log10y, then express x by y