If a⁴ + b⁴ = 14a²b², then let us show that log (a² + b²) = log a + log b + 2log2.

5

Let us prove:

x^{logy – logz} × y^{logz – logx} × z^{logx – logy} = 1

6

If then let us show that

7

If then let us show that xyz = 1

8

If then let us show that xyz = 1

(a)x^b+c . y^c+a . z^a+b = 1

(b)