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Q4 of 65 Page 10

Let us solve :
(2x+1)² + (x+1)² = 6x + 47

Hence , x = 3 or x = -3

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3

If 2/3 and -3 are the two roots of the quadratic equation ax² + 7x + b = 0, then let me calculate the values of a and b.

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3y² – 20 = 160 – 2y²

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(x-7)(x-9) = 195

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Questions · 65

1. Quadratic Equations in One Variable

1 2 3 4 4 4 4 5 6 6 6 6 6 6 6 6 1 1 1 1 2 2 3 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 1 2 3 4 5 6 7 8 9 10 10 10 10 10 10 10 11 11 11 11 11

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