Let us find the value of a, if one root of the equation x2+ax+3=0 is 1
The given equation is ![]()
Given one of the roots is 1.
So, 1 must satisfy the equation.
∴ (1)2 + a × 1 + 3 = 0
⇒ 1 + a + 3 = 0
⇒ a + 4 = 0
⇒ a = -4
Therefore, the value of a is -4.
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