Given, PQ = 7.5cm, ∠QPR = 45°, ∠PQR = 75°;
PQ = 7.5cm, ∠QPS = 60°, ∠PQS = 60°;
Let us draw ΔPQR and ΔPQS in such a way that the points R and S lie on the same side of PQ, let us draw the circum circle of ΔPQR and let us observe and write the position of the point S within, on and out side the circum circle. Let us find out its explanation.
Steps of Construction:

1. Construct ΔPQR of given dimensions.
2. Construct ΔPQS of given dimensions such that R and S lie on the same side of PQ.

3. Draw perpendicular bisector of PQ.

4. Draw perpendicular bisector of QR.

5. The point of intersection is the circumcenter. Name it as O.
6. With O as center and OR as radius, draw a circle.

7. The circle passes through P,Q and R and is thus the circumcircle of this triangle.
We observe that the circumcircle also passes through S, i.e. S lies on the circle. This is because sum of the adjacent angles of the base of both the triangles are equal. That makes ∠PRQ = ∠PSQ.
We know that angle in the same segment of a circle are equal. That’s why S lies on the circle.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.