Let us draw the following triangles and by drawing incircle of each circle, let us write by measuring the length of inradius in each case.
Let us draw an equilateral triangle having 7 cm. length of each side. By drawing the circumcircle and incircle, let us find the length of circum radius and inradius and let us write whether there is any relation between them.
Steps of Construction:
1. Construct triangle of given dimensions.
2. Name it as ΔABC.
3. Draw angle bisector of ∠A.
4. Draw angle bisector of ∠B.
5. They intersect at O.
6. Draw perpendicular on AB through O.
7. The perpendicular intersects with AB at P.
8. With O as center and OP as radius, draw a circle.
9. The inradius of the triangle, OP = 2.02cm.
10. We know that the incenter and circumcenter of equilateral triangle is same.
11. With O as center and OC as radius, draw a circle.
12. The circumradius of triangle, OC = 4.04cm.
We observe that circumradius = 2×inradius.
Couldn't generate an explanation.
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