Q1 of 53 Page 31

Simplify:

10−1 × 102 × 10−3 × 104 × 10−5 × 106;

Since the bases are same so their powers are solved algebraically

10−1 × 102 × 10−3 × 104 × 10−5 × 106 = 10(-1 + 2-3 + 4-5 + 6)


On solving we get,


10−1 × 102 × 10−3 × 104 × 10−5 × 106 = 103


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