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Q2 of 53 Page 32

Can you find two integers m,n such that 2^{m + n} = 2^mn ?

2^{m + n} = 2^mn

⇒ m + n = mn

Let m = n

So we get

2m = m²

⇒ m = 2

Since m = n, so

n = 2

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Questions · 53

10. Exponents

1 1 1 2 2 2 3 1 1 2 3 1 1 2 3 4 1 1 2 3 1 1 1 2 3 1 1 1 2 3 1 1 1 2 3 4 4 4 1 1 1 1 1 2 3 3 3 4 5 6 7 8 9

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