Find the median for the following frequency distribution table:

The given distribution is in inclusive form. It should be converted in exclusive form

Upper limit of 1^st interval is 119

Lower limit of 2^nd interval is 120

= = = 0.5

Actual upper limit = Stated upper limit +

Actual lower limit = Stated lower limit –

As we have sum of frequency to be (N) 50

As it is an even number

It has 2 middle scores

=

For finding 25^th and 26^th term we need to find cumulative frequency

25 and 26 can be covered under Cumulative frequency 29

∴ 129.5 – 139.5 is Median class

⇒ Low real limit (LRL) = 129.5

⇒ Frequency of median class (f_m) = 15

⇒ Cumulative Frequency of above median class (f_c) = 14

⇒ Size of class interval (i) = 10

Median = LRL +

= 129.5 +

= 129.5 +

= 129.5 + = 129.5 + 7.33 = 136.83