Find the median for the following frequency distribution table:

As we have sum of frequency to be (N) 40

As it is an even number

It has 2 middle scores

=

For finding 20^th and 21^th term we need to find cumulative frequency

20 and 21 can be covered under Cumulative frequency 27

∴ 15-20 is Median class

⇒ Low real limit (LRL) = 15

⇒ Frequency of median class (f_m) = 10

⇒ Cumulative Frequency of above median class (f_c) = 17

⇒ Size of class interval (i) = 5

Median = LRL +

= 15 +

= 15 +

= 15 + = 15 + 1.66 = 16.66