If the length, breadth, and height of one packet of one gross match box are 2.8dcm. and 0.9dcm respectively, then let us calculate the volume of one match box. [one gross=12dozen]. But if the length and breadth of one matchbox be 5 cm and 3.5 cm , then let us calculate the height of it.
Given,
Length of one gross match box=2.8dcm
The breadth of one gross match box=0.9dcm
The height of one gross match box=1.5dcm
The volume of one gross match box=2.8×0.9×1.5
⇒ Volume of one gross match box =3.78dcm3
one gross=12dozen
1 dozen =12 units
Therefore, one gross=12×12units
one gross=144units
Therefore,
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⇒
[1dcm=100mm]
The volume of one match box=26.25cubic cm
Length of one match box=5cm
The breadth of one match box=3.5 cm
The height of one match box=? cm
The volume of one match box=26.25cubic cm
⇒ 5×3.5×height=26.25
⇒ ![]()
Height of one cube=1.5cm
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