Q16 of 35 Page 74

If the length, breadth, and height of one packet of one gross match box are 2.8dcm. and 0.9dcm respectively, then let us calculate the volume of one match box. [one gross=12dozen]. But if the length and breadth of one matchbox be 5 cm and 3.5 cm , then let us calculate the height of it.

Given,


Length of one gross match box=2.8dcm


The breadth of one gross match box=0.9dcm


The height of one gross match box=1.5dcm


The volume of one gross match box=2.8×0.9×1.5


Volume of one gross match box =3.78dcm3


one gross=12dozen


1 dozen =12 units


Therefore, one gross=12×12units


one gross=144units


Therefore,



[1dcm=100mm]


The volume of one match box=26.25cubic cm


Length of one match box=5cm


The breadth of one match box=3.5 cm


The height of one match box=? cm


The volume of one match box=26.25cubic cm


5×3.5×height=26.25



Height of one cube=1.5cm


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