The depth of a cuboidal pond with length of 20m and breadth of 18.5m is 3.2m, let us write by calculating the time required to irrigate whole water of the pond with a pump with capacity to irrigate 160 kilo L water per hour. If that quantity of water is poured on a paddy field with a ridge having the length of 59.2m and breadth of 40m then what is the depth of water in that field –let us write calculating it,[I cubic m = I kilo L]
Given, length of cuboidal pond = 20m
breadth of cuboidal pond = 18.5 m
height of cuboidal pond = 3.2m
Thus volume of cuboidal pond = length × breadth × height
= 20×18.5×3.2
= 1184 m3
According to question, time required to irrigate upto 160 L = 1 hr
As, 1m3 = 1000L
160L =
= 0.16 m3
So, time required to irrigate 1184 m3
hr.
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= 7400 hr
2nd part: Length of field = 59.2m
breadth of field = 40 m
Let height of field = H m
According to question,
Volume of field to be poured with water = volume of water
length ×breadth × height = 1184 m3
59.2 × 40 × H = 1184
H = ![]()
H = 0.5 m
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