Q15 of 27 Page 289

If the lengths of two diagonals of a rhombus are 24cm. and 10cm, the perimeter of the rhombus is

We know that the diagonals of a rhombus are perpendicular bisector to each other.


It can be solved using figure given below:



By applying Pythagoras theorem to ΔAOB, we get,


AB2 = 52 + 122


⇒ AB2 = 25 + 144


⇒ AB2 = 169


⇒ AB = √169 = 13 cm


Perimeter of rhombus = 4 × side


= 4 × AB


= 4 × 13 cm


= 52 cm

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