In the adjoining figure,
and
are parallel lines. The transversals
and
intersect at U on the line
. Given that ∠DWU = 110° and ∠CVP = 70°, find the measure of ∠QUS.

We know, ∠CVP = 70°,
∴∠UVW = 70° [∵ Vertically opposite angles]
Again,
⇒ ∠UWV + ∠DWU = 180°
⇒ ∠UWV = 180° - 110°
⇒ ∠UWV = 70°
In ΔUVW,
⇒ ∠UVW + ∠UWV + ∠VUW = 180°
⇒ 70° + 70° + ∠VUW = 180°
⇒ ∠VUW = 180° - 140° = 40°
∴ ∠QUS = ∠VUW = 40° [Vertically opposite angle]
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