Q6 of 59 Page 255

A particle accelerates from rest at a constant rate for some time and attains a constant velocity of 8 ms-1. Afterwards it decelerates with a constant rate and comes to rest. If the total time taken is 4 second, the distance travelled is:

Now, from the given velocity – time graph we can calculate the distance by calculating area under the graph.



Distance Travelled = Area under the graph


=


= 16 m


Hence option B is correct

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