In figure 5.18 if ∠x + ∠y = ∠p + ∠q then prove that AOB is a straight line.

Given:
∠x + ∠y = ∠p + ∠q
Theory
A ray possesses 360° when its to original position.
Taking the ray OB
∠x + ∠y + ∠p + ∠q
Forms out a complete circle
Hence;
⇒ ∠x + ∠y + ∠p + ∠q = 360°
If ∠x + ∠y = ∠p + ∠q
Then
(∠x + ∠y) + (∠p + ∠q) = 360°
(∠x + ∠y) + (∠x + ∠y) = 360°
2(∠x + ∠y) = 360°
⇒ (∠x + ∠y) =
= 180°
OA and OB are rays joint at O and angle possesses by them ∠ x and ∠ y sums to 180°
Then
⇒ AB is a straight line
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