Factorise.
x2 + 9x + 18
On comparing with standard quadratic equation that is ![]()
we have,
a = 1, b = 9 and c = 18
Now here,
Product a
c = 1
18 = 18
Factors of 18; 2
9 and 6
3
Sum should be b = + 9
From above factors (+ 6x + 3x)
will give + 9x sum
therefore + 9x is replaced by ( + 6x + 3x)
Now above eq. becomes
x2 + 6x + 3x + 18
⇒
; taking x common
⇒ (x + 3)(x + 6)
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