Factorise.

y² + 24y + 144

On comparing with standard quadratic equation that is

we have,

a = 1, b = + 24 and c = + 144

Now here,

Product a × c = 1 × 144 = 144

Factors of 144; 12 × 12; 24 × 6;144 × 1;

48 × 3; 72 × 2

Sum should be b = 24

From above factors (12y + 12y)

will give + 24y sum

therefore + 24 is replaced by ( + 12y + 12y)

Now above eq. becomes

; taking y and + 12 common

(y + 1)(y + 12)

Note: Try to find all factors of “c”, then choose from it that combination whose sum or difference give “b”