If one zero of the polynomial 3x2 – 8x + 2k + 1 is seven times of other then, Find the value of k.
The polynomial 3x2 – 8x + 2k + 1 is quadratic hence it will have two zeroes
Let one zero of polynomial be α
As the other one is 7 times hence it would be 7α
Thus, α and 7α are roots of 3x2 – 8x + 2k + 1
Compare 3x2 – 8x + 2k + 1 with ax2 + bx + c = 0
a = 3, b = –8 and c = 2k + 1
the sum of roots of quadratic = ![]()
![]()
Substituting values of b and a
![]()
![]()
The product of roots of quadratic = ![]()
![]()
Substituting values of c and a
![]()
Substituting the value of ![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
Hence the value of ![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.