Q11 of 18 Page 88

Find the HCF of 72 & 96 by Euclid division algorithm and express it in form 96 m+72 n where m and n are some integers.

According to Euclid’s Division Lemma, if a and b are any two positive integers then there exist two unique whole numbers q and r such that

a = b q + r,


where 0 ≤ r < b


Here, a is called the dividend,


b is called the divisor,


q is called the quotient and


r is called the remainder.


So, apply the lemma on 96 and 72.


We get,


96 = (72 × 1) + 24 …(i)


Since the remainder is not zero.


Apply the lemma again on 72 and 24.


We get,


72 = (24 × 3) + 0


We have finally got remainder as 0.


HCF (96, 72) = 24


Now, we need to express the HCF in the form 96m + 72n, where m and n are integers.


So, take equation (i),


96 = (72 × 1) + 24


24 = 96 – (72 × 1)


24 = 96 (1) – 72 (1)


24 = 96 (1) + 72 (-1)


Thus, 24 is expressed as


24 = 96 (1) + 72 (-1)


Where, m = 1 & n = -1 are integers.


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